(3x^2+x-4)(2x-5)=

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Solution for (3x^2+x-4)(2x-5)= equation: 


Simplifying
(3x2 + x + -4)(2x + -5) = 0

Reorder the terms:
(-4 + x + 3x2)(2x + -5) = 0

Reorder the terms:
(-4 + x + 3x2)(-5 + 2x) = 0

Multiply (-4 + x + 3x2) * (-5 + 2x)
(-4(-5 + 2x) + x(-5 + 2x) + 3x2 * (-5 + 2x)) = 0
((-5 * -4 + 2x * -4) + x(-5 + 2x) + 3x2 * (-5 + 2x)) = 0
((20 + -8x) + x(-5 + 2x) + 3x2 * (-5 + 2x)) = 0
(20 + -8x + (-5 * x + 2x * x) + 3x2 * (-5 + 2x)) = 0
(20 + -8x + (-5x + 2x2) + 3x2 * (-5 + 2x)) = 0
(20 + -8x + -5x + 2x2 + (-5 * 3x2 + 2x * 3x2)) = 0
(20 + -8x + -5x + 2x2 + (-15x2 + 6x3)) = 0

Combine like terms: -8x + -5x = -13x
(20 + -13x + 2x2 + -15x2 + 6x3) = 0

Combine like terms: 2x2 + -15x2 = -13x2
(20 + -13x + -13x2 + 6x3) = 0

Solving
20 + -13x + -13x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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